Channel member management

⚠️ You can only manage channel members if you are a Channel Owner or Manager. Workspace Owners and Admins can only manage channel members in public channels.

 

You can form two types of channels in Orchidea: public and private. Public channels are visible to everyone and anyone can post ideas on them. Private channels are only visible to those who are added as members to them.

If you have the necessary role to manage the channel settings, you can add new members and remove members from the channel. That way the relevant people can participate in proposal creation in the channels. Channels also make it easier to manage proposals and who they are considering.

Add users to the channel

  1. Go to the channel of your choice.
  2. Click on the -icon on the right.
  3. From there press on Add new members.

  4. On the Search and add users -field write the names of the users of your choice.
  5. Press on the names that you want to add.
  6. Click Submit to add the new members.


Remove users from a channel

  1. Go to the channel of your choice.
  2. Click on the -icon on the right.
  3. From under the Action-column press on the members you want to remove.

  4. Click on Yes to finish the removal.

 

Changing the Channel role of a channel user

  1. Go to the channel of your choice.
  2. Click on the -icon on the right.
  3. From under the Channel role-column press on the current role
  4. Choose the user's new role by clicking on it from the opening menu.
  5. The new role will automatically saved.

💡 - icon after the title will update the site if it doesn't automatically update.

 

Monitor in which channels a guest or user is a member of

If you want to see the channels of which a guest user is a member, head to the settings from -icon in the upper right corner and then choose user management from the list in the left navigation.

  • Then click on the name of the user you want to check.
  • In the opening window, click Member of, and you'll see a list of all channels a person is a member of.